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The degree of hydrolysis in hydrolic equ...

The degree of hydrolysis in hydrolic equilibrium `A^(-) + H_(2)O hArr HA + OH^(-)` at salt concentration of 0.001 M is `(K_(1) = 1 xx 10^(-5))`

A

` 1 xx 10^(-3)`

B

`1 xx 10^(-4)`

C

`5xx 10^(-4)`

D

`1 xx 10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(h) = (K_(w))/(K_(a)) = (10^(-14))/(1xx10^(-5)) = 10^(-9)`
`K_(h) = alpha^(2)C, alpha = sqrt((K_(h))/C)= sqrt((1xx10^(-9))/(0.001))= 1 xx 10^(-3)` .
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