The correct relation between hydrolysis constant `(K_(b))` and degree of hydrolysis `(alpha)` for the following equilibrium is

Options

A. `alpha = sqrt((K_(w.C))/(K_(a)))`
B. `alpha = sqrt((K_(w))/(K_(a).C))`
C. `alpha = sqrt((K_(a).C)/(K_(w)))`
D. `alpha = sqrt((K_(a))/(K_(w).C))`

Answer

B

Explanation

Salt of weak acid and strong Base .
`K_(h) = (K_(w))/(K_(a))`
`h = sqrt((K_(h))/c)`
`h = sqrt((K_(w))/(K_(a)c))`