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The pH of the solution containing 10 mL ...

The pH of the solution containing 10 mL of 0.1N NaOH and 10 mL of 0.05 N `H_(2)SO_(4)` would be

A

0

B

1

C

` gt 7 `

D

7

Text Solution

Verified by Experts

The correct Answer is:
C
No. of milli equivalents of NaOH = `10 xx 0.1 = 1 `
No. of milli equivalents of `H_(2)SO_(4) = 10 xx 0.05 = 0.5`
Remaining equivalents of NaOH = `1 - 0.5 = 0.5`
So the solution will be basic for which `pH gt 7 `
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