Home
Class 11
CHEMISTRY
A 100 mL 0.1m solution of ammonium nitra...

A 100 mL 0.1m solution of ammonium nitrate is diluted by adding 100 ml of water. The pH of the resulting solution will be (`pK_a` of acetic acid is nearly equal of `NH_4OH` )

A

`4.9`

B

`5.0`

C

`7.0`

D

`10.0`

Text Solution

Verified by Experts

The correct Answer is:
C

Hydrolysis of a salt of weak acid and weak base:
`pH = 7+1/2 (pK_(a)-pK_(b))=7`
as `pK_(a) approx pK_(b)`
Promotional Banner

Similar Questions

Explore conceptually related problems

When 0.2M solution of acetic acid is neutralised with 0.2M NaOH in 500 mL of water, the pH of the resulting solution will be: [pK_(a) of acetic acid = 4.74]

100 ml of a solution of HCl with pH value 3 is diluted with 400 ml of water. The new P^(H) of the solution is

100 ml of a solution of HCl with pH value 3 is diluted with 500 ml of water. The new P^(H) of the solution is

1 mL of 0.1 N HCl is added to 999 mL solution of NaCl. The pH of the resulting solution will be :

The pH of solution is 5.0 to a 10 mL of solution 990 mL of water is add then pH of the resulting solution is