Home
Class 11
CHEMISTRY
30 cc of M/3 HCl, 20cc of M/2 HNO(3) and...

30 cc of `M/3` HCl, 20cc of `M/2` `HNO_(3)` and 40 cc of `M/4 NaOH` solutions are mixed and the volume was made upto `1 dm^(3)`. The pH of the resulting solution is :

A

2

B

1

C

3

D

8

Text Solution

Verified by Experts

The correct Answer is:
A
Total milli equivalents of `H^(+)`
`= 20 xx 1/2 +30 xx1/3 = 20 `
Total milliequivalents of `OH^(-) = 40 xx 1/4 = 10 `
Thus, milliequivalents of `H^(+) ` left = `20 - 10 = 10 `
Total volume of solution = `1"dm"^(3) = 1000 mL `
`:. [H^(+)] = 10/1000 = 10^(-2)`
` rArr pH = - log [H^(+)] = - log (10)^(-2) = 2 `
Promotional Banner

Similar Questions

Explore conceptually related problems

5 mL of N-HCl , 20 mL of N//2 H_(2)SO_(4) and 30 mL of N//3 HNO_(3) are mixed together and the volume is made to 1 L . The normality of the resulting solution is

100 c.c of N/10 NaOH solution is mixed with 100 c.c of N/5 HCI solution and the whole volume is made to 1 litre . The pH of the resulting solution will be

10ml of N-HCl 20ml of N//2 H_(2)SO_(4) and 30 ml of N//3 HNO_(3) are mixed together and volume made to one litre. The normality of the resulting solution is -

5mL of N HCI, 20 mL of N//2 H_(2)SO_(4) and 30 mL of N//3 HNO_(3) are mixed together and volume made to one litre. The normality of the resulting solution is