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What is pH of 2xx10^(-8) molar HCl solut...

What is pH of `2xx10^(-8)` molar HCl solution ? Here log 2 = `0.301 and log 3 = 0.477`

A

`5.4`

B

`7.7`

C

`6.92`

D

`9.5`

Text Solution

Verified by Experts

The correct Answer is:
C
Solution is very dilute so concentration of `H^(+)` ions in HCl solution
`H^(+)` ions in water `+ H^(+)` is ion in HCl
` = 1 xx 10^(-7) + 2 xx 10^(-8) = 12 xx 10^(-8)`
Sp pH `= - log (12 xx 10^(-8)) = - log (2^(2) xx 3 xx 10^(-8))`
` = - 2 log 2 - log 3 + 8 log 10 = - 2 (0.301 ) - 0.477 + 8 = 6.92 `
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