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Henderson's equation is pH = pK(a) + log...

Henderson's equation is `pH = pK_(a) + log.(["salt"])/(["acid"])`. If the acid gets half neutralized the value of pH will be : `[pK_(a) = 4.30]`

A

`4.3 `

B

`2.15`

C

`8.60`

D

7

Text Solution

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The correct Answer is:
A
`rArr pH = 4.3 + log. (1//2)/(1//2) = 4.3 +log 1 , rArr pH = 4.3 + 0 = 4.3 `
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