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If 50ml of 0.2 M KOH is added to 40 ml o...

If `50ml` of `0.2 M KOH` is added to `40 ml` of `0.5 M HCOOH`, the `pH` of the resulting solution is (`K_(a)=1.8xx10^(-4)`)

A

`3.4`

B

`7.5`

C

`5.6`

D

`3.75`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(HCOOH,+,KOH,hArr,HCOOK,+,H_(2)O,),(40xx0.5,,50xx0.2,,0,,0,"Intial"),(20-10,,10-10,,10,,10,"Final"):}`
Moles of HCOOK = Moles of HCOOH
[salt] = [acid]
`pH = pK_(a)`
`= - log (1 .8 xx 10^(-4))`
`= 4 - log 1.8 = 3.75`
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