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1xx10^(-3)mole of HCl is added to a buff...

`1xx10^(-3)`mole of HCl is added to a buffer solution made up of 0.01 M acetic acid and 0.01 M sodium acetate. The final pH of the buffer will be (given, `pK_a` of acetic acid is 4.75 at `25^@` C)

A

`4.60`

B

`4.66`

C

`4.75`

D

`4.8`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(CH_(3)COO^(-), +,H^(+) ,to, CH_(3)COOH),(0.01,,0.001,,0.01),(0.01-0.001,,,,0.01+0.001),(=0.009,,,,=0.011):} `
`pH = pKa +log . (["salt"])/(["acid"]) = 4.75 +log. (0.009)/(0.011) = 4.66`
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