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The dissociation constant of H(2)S and H...

The dissociation constant of `H_(2)S` and `HS^(-)` are respectively `10^(-7)` and `10^(-13)` . The pH of 0.1 M aqueous solution of `H_(2)S` will be

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The correct Answer is:
4
Since `K_(a_(2)) lt lt lt K_(a_(1))` Thus, `H^(+)` ions are mainly obtained from the first step i.e.,
`H_(2)S hArr HS^(-)+H^(+)`
`:.[H^(+)]=sqrt(KC)=sqrt(10^(-7)xx10^(-1))=10^(-4)`
`:.pH=-log(10^(-4))=4`.
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