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100mL of pH =6 solution is diluted to 10...

100mL of `pH =6` solution is diluted to 1000mL by water. pH of the solution will increase by

Text Solution

Verified by Experts

The correct Answer is:
`0.7`
Before dilution , `[H^(+)]=10^(-6)M`
`:.[H^(+)]` from acid `=10^(-6)-10^(-7)=0.9xx10^(-6)M`
`M_(1)V_(1)=M_(2)V_(2)`
`0.9xx10^(-6)xx100=1000xxM_(2)`
`M_(2)=0.9xx10^(-7)M`
After dilution ,
Total `[H^(+)]=[H^(+)]` from acid `+[H^(+)]` from water
`=0.9xx10^(-7)M+10^(-7)M`
`=1.9xx10^(-7)M`
`pH=-log[H^(+)]=-log1.9xx10^(-7)`
`=7-log1.9~~7-0.3=6.7`
`:.` Increase in `pH=6.7-6=0.7`.
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