pH of a solution produced when an aqueous soution of `pH =6` is mixed with an equal volume of an aqueous solution of `pH =3` is about `:`

Answer

`3.3`

Explanation

Assume 1L of each solution
`[H_(3)O^(+)]` in solution of `pH=6` is `10^(-6)M`
`[H_(3)O^(+)]` in solution of `pH=3` is `10^(-3)M`
Total `[H_(3)O^(+)]=((10^(-3)+10^(-6))/(2))`
`=5.005xx10^(-4)`
`:.pH=4-log5.005~~3.3`