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Solid Ba(NO(3))(2) is gradually dissolve...

Solid `Ba(NO_(3))_(2)` is gradually dissolved in a `1.0xx10^(-4)M Na_(2)CO_(3)` solution. At what concentration of `Ba^(2+)` will a precipitate being to from ? `(K_(sp)` for `BaCO_(3)=5.1xx10^(-9))`

A

`4.1xx10^(-5)M`

B

`5.1xx10^(-5)M`

C

`8.1xx10^(-8)M`

D

`8.1xx10^(-7)M`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(Na_(2)CO_(3),,to,,2Na^(+),,+,,CO_(3)^(-2)),(1xx10^(-4)M,,,,2xx10^(-4)M,,,,1xx10^(-4)M):}`
`K_(sp)[BaCO_(3)]=[Ba^(+2)][CO_(3)^(-2)]`
`5.1xx10^(-9)=[Ba^(+2)]xx1xx10^(-4)`
`[Ba^(+2)]=5.1xx10^(-5)M`.
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