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What is the pH of the resulting solution...

What is the `pH` of the resulting solution when equal volumes of `0.1 M NaOH` and `0.01 M HCl` are mixed?

A

`12.65`

B

`2.0`

C

`7.0`

D

`1.04`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(1)V_(1)-N_(2)V_(2)=N.V`.
`0.1xx1-0.01xx1=Nxx2`
`[OH^(-)]=N_(R)=(0.09)/(2)=0.045` N
`pOH=-log(0.045)=1.35`
:. `pH=14-pOH =14-1.35=12.65`
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