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20mL of 0.1M(H(2)SO(4))solution is added...

20mL of `0.1M(H_(2)SO_(4))`solution is added to 30mL of `0.2M(NH_(4)OH)` soulution. The `._(p)H` of the resultant mixture is : `[._(p)k_(b) " of " NH_(4)OH=4.7]`.

A

`9.0`

B

`5.2`

C

`9.4`

D

`5.0`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(H_(2)SO_(4),,+,,2NH_(4)OH,,to,,(NH_(4))_(2)SO_(4),,+,,2H_(2)O),(2m.m,,,,6m.m,,,,,,,,),(-,,,,2mm,,,,2mm,,,,):}`
`pOH=4.7+log.(4)/(2)=5`
`pH=14-5=9`
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