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3 gram of acetic acid is mixed in 250 mL...

3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL of this solution is now taken is another container `1/2` mL of 5M NaOH is added to this. Find the pH of this solution. (`pK_a = 4.74`)

Text Solution

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The correct Answer is:
`5.22`
m mole of acetic acid in 29mL=2
m mole of HCl in 20ml =1
m mole of NaOH `=2.5`
`{:(CH_(3)COOH,,+,,NaOH("remaining"),,to,,CH_(3)COONa,,+,,"water"),(2,,,,3//2,,,,0,,0,,),(0.5,,,,0,,,,3//2,,,,):}`
`pH=pK_(a)+log.(3//2)/(2)`
`=4.75+log3=4.75+0.4771=5.2271~~5.23`
`=4.74+0.48=5.22`
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