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When 32.25 g of ethyl chloride is subjec...

When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction, the yield of alkene formed is 50%. The mass of the product formed is (atomic mass of Cl = 35.5)

A

14g

B

28 g

C

64.5 g

D

7 g

Text Solution

Verified by Experts

The correct Answer is:
D
`underset(32.45)underset(64.5)(C_(2)H_(5)) overset(-HCl) to underset(14)underset(28)(C_(2)H_(4))`
64.5 g `C_(2)H_(5)Cl` gives 28 g of `C_(2)H_(4)`
`32.25` g `C_(2)H_(5)Cl` gives `(28 xx 32.35)(64.5) = 14`
= 14 g of `C_(2)H_(4)`
Obtained product is 50% so mass of obtained alkene `= 14/2 = 7 g`
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