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A gas mixture contains 50% helium and 50...

A gas mixture contains `50%` helium and `50%` methane by volume. What is the percent by weight of methane in the mixture.

A

0.1997

B

0.2005

C

0.5

D

0.8003

Text Solution

Verified by Experts

The correct Answer is:
D
Solution contain `He + CH_(4)`
Their mol. Wt `=4 + 16 = 20`
% of `CH_(4) = ("wt. of " CH_(4))/("Total wt") xx 100 = 16/20 xx 100 = 80.0 %`
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