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Empirical formula of a compound is CH(2)...

Empirical formula of a compound is `CH_(2)O` and its vapour density is 30. Molecular formula of the compound is

A

`C_(3)H_(6)O_(3)`

B

`C_(2)H_(4)O_(2)`

C

`C_(2)H_(4)O`

D

`CH_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
B
Empirical formula `=CH_(2)O`
Empirical formula mass `= 12 + 2 + 16 = 30`
Mol. Mass `= 2 xx V.D = 2 xx 30 = 60`
`n = ("Mol. Mass")/("Empirical mass") = 60/30 = 2`
Molecular formula = `("Empirical formula")_(n)`
`=(CH_(2)O)_(2) = C_(2)H_(4)O_(2)`
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