Empirical formula of compound is CH(2)O....

Empirical formula of compound is `CH_(2)O`.If its molecular weight is 180 then the molecular formula of the compound is

A

`C_(3)H_(6)O_(3)`

B

`C_(4)H_(8)O_(4)`

C

`C_(6)H_(12)O_(6)`

D

`C_(5)H_(10)O_(5)`

Verified by Experts

The correct Answer is:

C

Molecular formula = `("Empirical formula")_(n)`
`n = ("Molecular weight")/("Empirical formula wt") = 180/30 = 6`
`=(CH_(2)O)_(6) = C_(6)H_(12)O_(6)`

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