If 0.24 g of a volatile liquid upon vaporization gives 45 ml of vapours at NTP.What will be the vapour density of the substance ? (Density of `H_(2) =0.089 gL^(-1))`

Answer

56

Explanation

45 mL of vapours at NTP weighs = 0.24 g
`:. 22400 mL` of the vapour at NTP weighs
` = 0.24/45 xx 22400 = 112 g`
Thus, mol. Mass ` = 112`
As Mol. mass ` = 2xx` vapour density
`:.` Vapour density `= ("Mol. Mass")/2 = 112/2 = 56`.