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In Carius method of estimation of haloge...

In Carius method of estimation of halogens `250 mg` of an organic compound gave `141 mg` of `AgBr`. The percentage of bromine in the compound is (atomic mass `Ag = 108, Br = 80`)

A

24

B

36

C

48

D

60

Text Solution

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The correct Answer is:
A
%X `= ("Atomic mass of Br")/("Molecular mass of AgBr")xx ("Wt. of AgBr")/("Wt. of organic Bromide") xx 100`
Thus, %`Br = 80/188 xx 141/250 xx 100 = 24`.
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