Home
Class 12
CHEMISTRY
A mineral consists of a cubic close-pack...

A mineral consists of a cubic close-packed structure formed by `O^(2-)` ions where half the octahedral voids are occupied by `Al^(3+)` and one eighth of the tetrahedral voids are occupied by `Mn^(2+)`. The chemical formula of the mineral is

A

`Mn_(3)Al_(2)O_(3)`

B

`MnAl_(2)O_(3)`

C

`MnAl_(4)`

D

`Mn_(2)Al_(2)O_(5)`

Text Solution

Verified by Experts

The correct Answer is:
B

Properties of ionic solid
Promotional Banner

Similar Questions

Explore conceptually related problems

In a cubic close packed structure (ccp) of mixed oxides, it is found that lattice has O^(2-) ions and one half of the octahedral voids are occupied by trivalent cations (A^(3+)) and one-eighth of the tetrahedral voids are occupied by divalent cations (B^(2+)) . Derive the formula of the mixed oxide.

In a CPS (close packed structure) of mixed oxides, it is found that lattice has O^(2-) (oxide ions), and one half of octahedral voids are occupied by trivalent cations (A^(3+)) and one-eight of tetrahedral voids are occupied by divalent cation (B^(2+)) . Derive formula of the mixed oxide.

In spinel structure, O^(2-) ions are cubic-closed packed, wherease 1/8th of the tetrahedral holes are occupied by A^(2+) cations and 1/2 of the octahedral holes are occupied by cations B^(3+) . The general formula of this compound is

In the spinel structure, oxides ions are cubical - closest packed whereas 1//8 th of tetrahedral voids are occupied by A^(2+) cation and 1//2 of octahedral voids are occupied by B^(2+) cations. The general formula of the compound having spinel structure is :

In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cation and 1/2 of octahedral voids are occupied by B^(+) cations. The general formula of the compound having spinel structure is:

In a cubic close packed structure of mixed oxides, the lattice is made up of oxide ions, one eight of tetrahedral voids are occupied by divalent (X^(2+)) ions, while one - half of the octahedral voids are occupied by trivalent ions (Y^(3+)) , then the formula of the oxide is