In the electrolysis of `NiSO_(4)` using Nickel electrodes the reaction that takes place at anode is

Options

A. `SO_(4)^(2-) to SO_(4) + 2e^(-)`
B. `Cu to Cu^(+) + e^(-)`
C. `2OH^(-) to H_(2)O + 1//2O_(2) + 2e^(-)`
D. `Cu to Cu^(2+) + 2e^(-)`

Answer

D

Explanation

Properties of ionic solid