Home
Class 12
CHEMISTRY
Zn(s) + Cu^(2+)(aq) rarr Zn^(2+)(aq) + C...

`Zn(s) + Cu^(2+)(aq) rarr Zn^(2+)(aq) + Cu(s)` The cell representation for the above redox reaction is

A

`Zn | Zn^(2+) || Cu^(2+) |Cu`

B

`Cu | Cu^(2+) || Zn^(2+) | Zn`

C

`Cu|Zn^(2+) || Zn | Cu^(2+)`

D

`Cu^(2+) | Zn || Zn^(2+) | Cu`

Text Solution

Verified by Experts

The correct Answer is:
A
Properties of ionic solid
Promotional Banner

Similar Questions

Explore conceptually related problems

The emf of the cell reaction Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +Cu(s) is 1.1V . Calculate the free enegry change for the reaction. If the enthalpy of the reaction is -216.7 kJ mol^(-1) , calculate the entropy change for the reaction.

The reaction Co(s) + Cu^(2+)(aq) rarr Co^(2+)(aq) + Cu(s) is-

Assertion : Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s) can be split into following two half reactions underset(("oxidation half reaction"))(Zn(s)rarrZn^(2+)+2e^(-)) Reason : Every redox reaction can be split into two reactions, one representing loss of electrons and the other representing gain of electrons. Cu^(2+)(aq)+2e^(-)rarrunderset(("reduction half reaction"))(Cu(s))

E^(@) for the cell Zn(s)|Zn^(2+)(aq)|Cu^(2+)(aq)|Cu(s) is 1.1V at 25^(@)C the equilibrium constant for the cell reaction is about

Zn(s)+CuSO_4(aq) to ZnSO_4(aq) + Cu(s) The above equation is an example of: