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The equilibrium constant of the followin...

The equilibrium constant of the following redox rection at 298 K is `1 xx 10^(8)`
`2Fe^(3+) (aq.) +2I^(-) (aq.) hArr 2Fe^(2+)(aq.) +I_(2) (s)`
If the standard reducing potential of iodine becoming iodide is +0.54 V. what is the standard reduction potential of `Fe^(3+)//Fe^(2+)` ?

A

`+1.006 V`

B

`– 1.006 V`

C

`+0.77 V`

D

`– 0.77 V`

Text Solution

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The correct Answer is:
C
Properties of ionic solid
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