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Given : E(Fe^(3+)//Fe)^(@) = -0.036V, E(...

Given : `E_(Fe^(3+)//Fe)^(@) = -0.036V, E_(FE^(2+)//Fe)^(@)= -0.439V`. The value of electrode potential for the change, `Fe_(aq)^(3+) + e^(-)rightarrow Fe^(2+) (aq)` will be :

A

`-0.072V`

B

`0.385V`

C

`0.770V`

D

`-0.270V`

Text Solution

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The correct Answer is:
C
Properties of ionic solid
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