Home
Class 12
CHEMISTRY
The emf of the cell in which the followi...

The emf of the cell in which the following reactions,
`Zn(s)+Ni^(2+) (0.1M) rarr Zn^(2+) (1.0 M) + Ni(s)` occurs, is found to 0.5105 V at 298 K. The standard emf of the cell is :

A

0.5400V

B

0.4810V

C

0.5696V

D

`-0.5105V`

Text Solution

Verified by Experts

The correct Answer is:
A
Properties of ionic solid
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the EMF of the cell in whiCHM the following reaction takes place : Ni(s)+2Ag^(o+)(0.002M) rarr Ni^(2+)(0.160M)+2Ag(s)

Calculate the e.m.f. of the cell in which the following reaction takes place : Ni(s) +2Ag^(+)(0.002 M)to Ni^(2+)(0.160 M)+2Ag(s) Given E_(cell)^(@) =1.05 v

Consider the following reaction, Zn(s)+Cu^(2+) (0.1 M) rarr Zn^(2+) (1 M)+Cu(s) above reaction, taking place in a cell, E_("cell")^(@) is 1.10 V. E_("cell") for the cell will be (2.303 (RT)/(F)=0.0591)

Find the emf of the cell Zn(s)|Zn^(+2)(0.01 M)|KCI "saturated" |Zn^(+2)(1.0 M)|Zn(s)

The emf of a cell corresponding to the reaction. Zn(s)+ 2H^(+)(aq)rightarrow Zn^(2+)(0.1M)+H_(2) (g,1atm) is 0.28 V at 25^(@) C . Calculate pH of the solution.