Home
Class 12
CHEMISTRY
The photoelectric current from Na (Work ...

The photoelectric current from Na (Work function, w0 = 2.3 eV) is stopped by the output voltage of the cell `Pt(s) H_(2)"(g, 1 Bar) HCl (aq. pH =1) "|AgCl (s)|Ag(s)`.
The pH of aq. HCl required to stop the photoelectric current form `K(w_(0) = 2.25 eV)`, all other conditions remaining the same, is _______ `xx10(-2)` (to the nearest integer).
Given,
`2.303(RT)/(F)=0.06V,E_(AgCl|Ag|Cl^(-))^(@)=0.22V`

Text Solution

Verified by Experts

The correct Answer is:
142
Properties of ionic solid
Promotional Banner

Similar Questions

Explore conceptually related problems

The measured voltage of the cell, Pt(s)|H_2(1.0"atm")|H^+(aq)||Ag^+(1.0M)|Ag(s) is 1.02 V " at " 25^@C . Given E_("cell")^@ is 0.80 V, calculate the pH of the solution .

The cell Pt|H_(2)(g,01 bar) |H^(+)(aq),pH=x||Cl^(-)(1M)|Hg_(2)Cl_(2)|Hg|Pt has emf of 0.5755 V at 25^(@)C the SOP of calomel electrode is -0.28V then pH of the solution will be

For the cell Cu (s) | Cu ^(2+) (aq) (0.1 M) || Ag ^(+) (aq) (0.01 M) | Ag (s) the cell potential E _(1) = 0.3095 V For the cell Cu (s) | Cu ^(+2) (aq) (0.01 M) || Ag ^(+) (aq)( 0. 001 M) | Ag (s) the cell potential = _______ xx 10 ^(-2) V. (Round off the Nearest Integer). [Use : (2.303 RT)/(F) =0.059 ]

The EMF of the following cellis 1.05V at 25^(@)C: Pt,H_(2)(g)(1.0 atm)|NaOH(0.1m),NaCl(0.1M)|AgCl(s),Ag(s) a. Write the cell reaction, b. Calculate pK_(w) of water.

In the cell Pt(s)|H_(2)(g,1bar)|HCl (aq)| AgCl(s)|Ag(S)|Pt(s) the cell potential is 0.92V when a 10^(-6) mola1 HCl Ssolution is used. The standard electrode potential of (ACl//Ag,Cl^(-)) electrode is : {given, (2.30Rt)/(F) = 0.6V at 298K}

In the cell Pt (s) | H_(2) (g, 1 " bar")| HCl (aq)| AgCl(s) | Ag(s) | Pt(s) the cell potential is 0.92 V when a 10^(-6) molal HCl solution is used. The standard electrode potential of (AgCl//Ag, Cl^(-)) electrode is {Given, (2.303RT)/(F) = 0.06V at 298 K}