For the cell
`Cu (s) | Cu ^(2+) (aq) (0.1 M) || Ag ^(+) (aq) (0.01 M) | Ag (s)`
the cell potential `E _(1) = 0.3095 V`
For the cell
`Cu (s) | Cu ^(+2) (aq) (0.01 M) || Ag ^(+) (aq)( 0. 001 M) | Ag (s)`
the cell potential = _______ `xx 10 ^(-2) V.`
(Round off the Nearest Integer).
[Use : `(2.303 RT)/(F) =0.059`]

Answer

28

Explanation

Properties of ionic solid