Home
Class 12
CHEMISTRY
Consider a first order gas phase decomp...

Consider a first order gas phase decomposition reaction given below:
`A(g) to B_(g) + C_(g)`
The initial pressure of the system before decomposition of A was `p_(i)`. After lapse of time `t'`. Total pressure of the system increased by x units and became `P_(t)`. the rate constant k for the reaction is given as

A

`k=(2.303)/(t)log.(p_(i))/(p_(i)-x)`

B

`k=(2.303)/(t)log.(p_(i))/(2p_(i)-p_(t))`

C

`k=(2.303)/(t)log.(p_(i))/(2p_(i)+p_(t))`

D

`k=(2.303)/(t)log.(p_(i))/(p_(i)+x)`

Text Solution

Verified by Experts

The correct Answer is:
B
Properties of ionic solid
Promotional Banner

Similar Questions

Explore conceptually related problems

Consider a first order gas phase decompostion reaction gives below A(g) to B(g) to C(g) The initial pressure of the system before decomposition of A p_(i) . After lapse of time 't' total pressure of the system increased by x units and became p_(t) . The rate constant K for the reaction is given as....... .

Consdier a first order gas phase reaction, A(g) rarr 2B(g) + C(g) The initial pressure taking only A in a rigid vessel was found to be P atme. After a lapse of 10 minutes, the pressure of the system increases by x units and became P_(10) atm. The rate constant for the reaction is given by :

For a first order gas phase reaction : A_((g)) to 2B_((g)) +C_((g)) P_(0) be initial pressure of A and P_(t) the total pressure at time 't'. Integrated rate equation is :

For the first order reaction A(g) rarr 2B(g) + C(g) , the initial presuure is P_(A) = 90 m Hg , the pressure after 10 minutes is found to be 180 mm Hg . The rate constant of the reaction is

For a gas phase first order reaction, A(g) rightarrow B(g)+2C(g)+D(g) The initial pressure was P_(0) While pressure after 't' time becomes P_(t) ( P_(t) > P_(0) ). The expression for the rate constant (K) would be