Home
Class 12
CHEMISTRY
Rate constant k varies with temperature ...

Rate constant k varies with temperature T(k) as given by equation
`logk=logA-(E_(a))/(2.303RT)`
A plot between log k and `(1)/(T)` is straight line from the graph we can say

A

`E_(a)=2.303Rxx"slope"`

B

`E_(a)=2.303R^(2)xxtantheta`

C

`E_(a)=Rtantheta`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

Properties of ionic solid
Promotional Banner

Similar Questions

Explore conceptually related problems

Variation of equiibrium constant K with temperature T is given by van 't Holf equation, log K=logA-(DeltaH^(@))/(2.303RT) A graph between log K and T^(-1) was a straight line as shown in the figure and having theta=tan^(-1)(0.5)"and"OP=10 . Calculate: (a) DeltaH^(@) (standard heat of reaction)when T=300K, (b) A (pre-exponetial factor), (c) Equilibrium constant K at 300 K, (d) K "at" 900 K "if" DeltaH^(@) is independent of temperature.

The graph between log k versus 1//T is a straight line.

Rate constant k varies with temperature by equation, log k (min+^(-1))=5-(2000)/(T(K)) We can conclud:

Rate constant k varies with temperature by equation log k (min^(-1)) = log 5 - (2000 kcal)/(RT xx 2.303) . We can conclude that

A graph plotted between log k vs (1)/(T) is represented by

The rate constant 'k'. For a reaction varies with temperature 'T' according to the question. log k = log A-(E_(a))/(2.303R)(1/T) Where E_(a) is the activation energy. When a graph is plotted for log k vs 1//T , a straight line with a slope of -4250 K is obtained. Calcualte E_(a) for this reaction.

(a) For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction. (b) Rate constant 'K' of a reaction varies with temperature 'T' according to the equation : logK=logA-E_a/(2.303R)(1/T) Where E_a is the activation energy. When a graph is plotted for log k Vs 1/(T) a straight line with a slope of -4250 K is obtained. Calculate E_a for the reaction. ( R=8.314JK^(-1)mol^(-1) )