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Consider the reaction, N(2) + 3H(2) rarr...

Consider the reaction, `N_(2) + 3H_(2) rarr 2NH_(3)` carried out at constant temperature and pressure. If `Delta H and Delta U` are the enthalpy and internal energy changes for the reaction, which of the following expressions is true?

A

`Delta H = 0`

B

`Delta H= Delta U`

C

`Delta H lt Delta U`

D

`Delta H gt Delta U`

Text Solution

Verified by Experts

The correct Answer is:
C
At constant P or T
`Delta H= Delta U + Delta n_(g) RT rArr Delta n_(g)= n_(p)- n_(R) =2-4= -2`
`therefore Delta H lt Delta U`
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