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DeltaE^(@) of combustion of isobutylene ...

`DeltaE^(@)` of combustion of isobutylene is `-X kJ mol^(-1)`. The value of `DeltaH^(@)` is

A

`= Delta E^(@)`

B

`gt Delta E^(@)`

C

`=0`

D

`lt Dleta E^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(CH_(3))_(2)C= CH_(2)(g) + 6O_(2)(g) rarr 4CO_(2)(g) + 4H_(2)O(l)`
`Delta n_(g)= 4- 6= -2` (i.e., negative)
we know that `Delta H= Delta E+ Delta n_(g)RT= Delta E- (Delta n_(g)) RT (because Delta n_(g)= -ve)`
`therefore Delta H lt Delta E`
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