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The work done by the gas liberated when ...

The work done by the gas liberated when 50 g of iron (molar mass 55.85 g `mol^(-1)`) reacts with hydrochloric acid in an open beaker at `25^(@)C`

A

Zero

B

`-2.2` kJ

C

2.2kJ

D

0.22kJ

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(((50)/(55.85)"moles"))(Fe(s)) + 2HCl(aq) rarr FeCl_(2)(aq) + underset(((50)/(55.85) "moles"))(H_(2)(g))`
Moles of iron = Moles of hydrogen gas `= (50)/(55.85)= Delta n_(g)`
`R= 8.314 J "mole"^(-1) K^(-1)`
`T= 25+273= 298K`
Work done by `H_(2)` gas `W = - Delta n_(g)RT= (-50)/(55.85) xx 8.314 xx 298 xx 10^(-3)kJ= -2.2kJ`
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