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The sublimation energy of I(2) (solid) i...

The sublimation energy of `I_(2)` (solid) is 57.3 KJ/mole and enthalpy of fusion is 15.5 KJ/mole. The enthalpy of vapourisation of `I_(2)` is

A

41.8 kJ/mol

B

`-41.8` kJ/mol

C

72.8kJ/mol

D

`-72.8` kJ/mol

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(2)(s) rarr I_(2)(g), Delta H_(1)= +57.3` kJ/mol
`I_(2)(s) rarr I_(2)(l), Delta H_(2)= +15.5` kJ /mol
Hence, for the conversion -
`I_(2)(l) rarr I_(2)(g) " " Delta H= Delta H_(1)- Delta H_(2)= 57.3 - 15.5 = +41.8` kJ/mol
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