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In an isobaric process, the ratio of hea...

In an isobaric process, the ratio of heat supplied to the system `(dQ)` and work done by the system `(dW)` for diatomic gas is

A

`1:1`

B

`7:2`

C

`7:5`

D

`5:7`

Text Solution

Verified by Experts

The correct Answer is:
B
`-(dQ)/(dW) = (dQ)/(dQ- dE), dE= dW + dQ, -dW= dQ- dE= (nc_(p) dT)/(nc_(p) dT- nc_(v) dT)= (c_(p))/((c_(p)- c_(v))) = (7R)/(2R)` {for diatomic of gas `c_(p)= (7R)/(2)`}
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