Home
Class 11
CHEMISTRY
For the isothermal reversible expansion ...

For the isothermal reversible expansion of an ideal gas

A

`Delta H gt 0 and Delta U= 0`

B

`Delta H gt 0 and Delta U lt 0`

C

`Delta H= 0 and Delta U= 0`

D

`Delta H = 0 and Delta U gt 0`

Text Solution

Verified by Experts

The correct Answer is:
C
Isothermal means `Delta T = 0` If temperature is constant, means `Delta U = 0` as whole energy is used in work done and due to reversible expansion `Delta Η = 0`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Correct relation for isothermal reversible expansion of an ideal gas is DeltaS = 0 DeltaG = - T DeltaS DeltaH != 0 DeltaU != 0

In an isothermal irreversible expansion of an ideal gas as per IUPAC sign convention :

Calculate the work done during isothermal reversible expansion of one mole ideal gas from 10 atm to 1 atm at 300 K .

Calculate Q and w for the isothermal reversible expansion of one mole an ideal gas from an initial pressure of 1.0 bar to a final pressure of 0.1 bar at a constant temperature of 273 K respectively.

Calculate the DeltaH for the isothermal reversible expansion of 1 mole of an ideal gas from initial pressure of 0.1 bar at a constant temperature at 273K .

For an isothermal free expansion of an ideal gas,

Calculate q,w , and DeltaU for the isothermal reversible expansion of one mole of an ideal gas from an initial pressure of 2.0 bar to a final pressure of 0.2 bar at a constant temperature of 273K .