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An engine operating between 150^(@)C and...

An engine operating between `150^(@)C` and `25^(@)C` takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is

A

147.7 J

B

157.75J

C

165.85 J

D

169.95 J

Text Solution

Verified by Experts

The correct Answer is:
A
`T_(2)= 150 + 273 = 423 K, T_(1)= 25+ 273= 298KQ= 500K`
`(W)/(Q) = (T_(2)- T_(1))/(T_(2)), W = 500 ((423 - 298)/(423))= 147.7J`
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