Entropy changesh for the process, `H_(2)O(l) to H_(2)O` at normal pressure and 274K are given below
`triangleS_("system") =-22.13, triangleS_("surr")=+22.05`, the process is non spontaneous because

Options

A. `Delta S_("system")` is -ve
B. `Delta S_("surr")` is +ve
C. `Delta S_(u)`, is-ve
D. `Delta S_("system") ne Delta S_("surr")`

Answer

C

Explanation

`Delta S_(u)= Delta S_("system") + Delta S_("surrounding") = -22.13 + 22.05 = -0.08`
For a spontaneous process, `Delta S_(u)` must be positive i.e.,
`Delta S_(u)= Delta S_("system") + Delta S_("surrounding") gt 0`