The latent heat of melting of ice at 0^(...

The latent heat of melting of ice at `0^(@)C` is 6 kJ `"mol"^(-1)` . The entropy change during the melting in `JK^(_1) "mol"^(-1)` is closest to-

A

22

B

11

C

`-11`

D

`-22`

Verified by Experts

The correct Answer is:

A

`Delta S= (Delta H_("melting"))/(T_(F.P)) = (6 xx 1000)/(273) (J)/(K)= 21.978 ~~ 22 J//K`

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