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The standard enthalpy of formation of H(...

The standard enthalpy of formation of `H_(2)O_((l)) and Fe_(2)O_(3(s))` are respectively `- 286kJ mol^(-1) and - 824 kJ mol^(-1)`. What is the standard enthalpy change for the following reaction `Fe_(2)O_(3(s)) + 3H_(2(g)) rarr 3H_(2)O_((l)) + 2Fe_((s))`

A

`-538 kJ mol^(-1)`

B

`+538 kJ mol^(-1)`

C

`-102 kJ mol^(-1)`

D

`-34kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`Fe_(2) O_(3(s)) + 3H_(2(g)) rarr 3H_(2)O_((l)) + 2Fe_((s))`
`Delta_(r) H^(@) = Sigma Delta_(f) H_(("Products"))^(@) - Sigma Delta_(f)H^(@)` (Reactants)
`rArr Delta_(r) H^(@) = 3(-286)- (-824)`
`[because Delta_(f)H^(@) "for " Fe_((s)), H_(2(g)) = 0]`
`= -858 + 824= -34 kJ mol^(-1)`
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