If (i) `C+ O_(2) rarr CO_(2)`, (ii) `C +1//2O_(2) rarr CO`, (iii) `CO+ 1//2O_(2) rarr CO`, the heats of reaction are `Q.-12, -10` respectively. Then Q=

Options

A. `-2`
B. 2
C. `-22`
D. `-16`

Answer

C

Explanation

`C+ O_(2) rarr CO_(2), Delta H= q`
`C + 1//2O_(2) rarr CO, Delta H= -12` ...(i)
`CO +1//2O_(2) rarr CO_(2), Delta H= -10` ...(ii)
adding equation (i) and (ii) we can get
`Delta H= -12 + (-10) = -22`