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The enthalpy of certain reaction at 273 ...

The enthalpy of certain reaction at `273 K` is `-20.75 kJ`. The enthalpy of the same reaction at `373 K` provided heat capacities fo reactants and products are the same) will be

A

`-20.75` kJ

B

`-2075` kJ

C

Zero

D

`-20.75 xx (373)/(273)kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
By Kirchhoff's equation : `(Delta H_(T_(2)) - Delta H_(T_(1)))/(T_(2)- T_(1)) = C_(p)` (Product) `-C_(p)` (Reactant)
`(Delta H_(T_(2)) - (-20.75))/(Delta T)= 0 rArr Delta H_(T_(2))= -20.75kJ`
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