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If C+O(2) to CO(2)+94.2kcal H(2)+(1)/...

If `C+O_(2) to CO_(2)+94.2kcal`
`H_(2)+(1)/(2)O_(2) to H_(2)O+68.3"kcal"`
`CH_(4)+2O_(2) to CO_(2)+2H_(2)O+210.8"kcal"`
Then, the heat of formation of methane will be

A

47.3 kcal

B

20.0 kcal

C

45.9 kcal

D

`-47.3` kcal

Text Solution

Verified by Experts

The correct Answer is:
B
`C + O_(2) rarr CO_(2) + 94.2 kcal` ...(i)
`H_(2) + (1)/(2) O_(2) rarr H_(2)O + 68.3` kcal ...(ii)
On multiplication of eq (ii) by 2 and than adding in eq (i)
`C+ 2H_(2) + 2O_(2) rarr CO_(2) + 2H_(2)O + 230.8` kcal ...(iii)
On subtracting eq (iii) by following eq.
`CH_(4) + 2O_(2) rarr CO_(2) + 2H_(2)O + 210.8` kcal we get, `C + 2H_(2) rarr CH_(4) Delta H= 20` kcal
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