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When 50 cm^(3) of 0.2 N H(2)SO(4) is mix...

When `50 cm^(3)` of `0.2 N H_(2)SO_(4)` is mixed with `50 cm^(3)` of `1 N KOH`, the heat liberated is

A

11.46 kJ

B

57.3 kJ

C

573 kJ

D

573J

Text Solution

Verified by Experts

The correct Answer is:
D
For complete neutralization of strong acid and strong base energy released is 57.32kJ/mol
No. of g eq of `H_(2)SO_(4) = (0.2 xx 50)/(1000) = 10^(-2)`
No. of eq of KOH `= (1)/(1000) xx 50 = 5 xx 10^(-2)`
So `=57.32 xx 10^(-2) = 0.5732kJ = 573.2` Joule
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