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From the following bond energies H-H b...

From the following bond energies
`H-H` bond energy `431.37 kJ mol^(-1)`
`C=C` bond energy `606.10 kJ mol^(-1)`
`C-C` bond energy `336.49 kJ mol^(-1)`
`C-H` bond energy `410.5 kJ mol^(-1)`
Enthalpy for the reaction
`overset(H)overset(|)underset(H)underset(|)(C )=overset(H)overset(|)underset(H)underset(|)(C )+H-HtoH-overset(H)overset(|)underset(H)underset(|)(C )-overset(H)overset(|)underset(H)underset(|)(C )-H`
will be

A

1523.6 kJ `mol^(-1)`

B

`-243.6 kJ mol^(-1)`

C

`-120.0 kJ mol^(-1)`

D

553.0 kJ `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`[(4 xx 410.5) + 606.1 +431.3] - [(6 xx 410.5) + 336.49] = -120.0kJ mol^(-1)`
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