Home
Class 11
CHEMISTRY
DeltaH and DeltaS for a reaction are +30...

`DeltaH` and `DeltaS` for a reaction are `+30.558 kJ mol^(-1)` and `0.066 kJ mol^(-1)` at `1` atm pressure. The temperature at which free energy is equal to zero and the nature of the reaction below this temperature are

A

483 K, spontaneous

B

443 K, non-spontaneous

C

443 K, spontaneous

D

463 K, non-spontaneous

Text Solution

Verified by Experts

The correct Answer is:
D

Negative value of `DeltaG` indicates that the process is spontaneous. Spontaneous process leads to the lowering of free energy `(Delta G)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The value of DeltaH and DeltaS for a reaction are respectively 30 kJ mol^(-1) and 100JK^(-1)mol^(-1) . Then temperature above which the reaction will become spontaneous is:

DeltaH and DeltaS for the reaction: Ag_(2)O(s) rarr 2Ag(s) +(1//2)O_(2)(g) are 30.56 kJ mol^(-1) and 66.0 J JK^(-1) mol^(-1) respectively. Calculate the temperature at which free energy change for the reaction will be zero. Predict whether the forward reaction will be favoured above or below this temperature.

The values of DeltaH and Delta S of a certain reaction are -400 kJ mol^-1 and -20 kJ mol^-1 K^-1 respectively. The temperature below which the reaction is spontaneous is _________.

DeltaH and DeltaS for the system H_2O_((l))hArr H_2O_((g)) at 1atm are 40.63 kJ mol^(-1) and 108.8 JK^(-1) mol^(-1) respectively. The temperature at which the rates of forward and backward reactions will be same:

For a reaction, DeltaH=10000" kJ "mol^(-1) and DeltaS=25" kJ "k^(-1)mol^(-1) . The minimum temperature, above which the reaction would be spontaneous is

Delta H and Delta S for the reaction, Ag_(2)O(s)to 2A(s)+(1)/(2)O_(2)(g) , are 30.56 kJ mol^(-1) and 66.0 J mol^(-1) respectively. Calculate the temperature at which this reaction will be at equilibrium. Predict whether the forward reaction will be favoured above or below this temperature.