The enthalpies of combustion of carbon and carbon monoxide are `-393.5` and `-283` kJ `mol^(-1)` respectively. The enthaly of formation of carbon monoxide per mole is :

Options

A. `− 676 5. kJ`
B. 676 5. kJ
C. 110 5. kJ
D. `-110.5 KJ`

Answer

D

Explanation

`C(s) + O_2(g) to CO_2(g)`
`DeltaH = -393.5 kJ mol^(-1)…(i)`
`CO(g) + 1//2O_2(g) to CO_2(g)`
`DeltaH = -283 kJ mol^(-1)`…(ii)
On subtracting equation (ii) from equation (i)
We get
`C(s) + O_2 (g) to CO(g) , DeltaH = - 110.5 kJ mol^(-1)`
The enthalpy of formation of carbon monoxide per
`"mole" = -110.5 kJ mol^(-1)`.