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The combustion of benzene (l) gives CO(2...

The combustion of benzene (l) gives `CO_(2)(g)` and `H_(2)O(l)`. Given that heat of combustion of benzene at constant volume is `–3263.9 kJ mol^(–1)` at `25^(@)C`, heat of combustion (in kJ` mol^(–1)`) of benzene at constant pressure will be
(R = 8.314 JK–1 mol–1)

A

3260

B

– 3267.6

C

4152.6

D

– 452.46

Text Solution

Verified by Experts

The correct Answer is:
B
`C_6 H_(6(l)) + 7.5 O_(2(g)) to 6CO_(2(g)) + 3H_2O_((l))`
`Deltan_((g)) = 6 - 7.5 = -1.5`
`DeltaH = DeltaE + Deltan_((g)) RT`
`DeltaH = - 3263.9 kJ-(1.5 xx 8.314 xx298)/(1000) kJ = - 3267.6 kJ`
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